Integrand size = 19, antiderivative size = 286 \[ \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx=-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}-\frac {56 b (a+b x)^{5/2}}{5 d^2 \sqrt [4]{c+d x}}-\frac {224 b^2 (b c-a d) \sqrt {a+b x} (c+d x)^{3/4}}{15 d^4}+\frac {112 b^2 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d^3}+\frac {448 b^{5/4} (b c-a d)^{11/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} E\left (\left .\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{15 d^5 \sqrt {a+b x}}-\frac {448 b^{5/4} (b c-a d)^{11/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{15 d^5 \sqrt {a+b x}} \]
-4/5*(b*x+a)^(7/2)/d/(d*x+c)^(5/4)-56/5*b*(b*x+a)^(5/2)/d^2/(d*x+c)^(1/4)+ 112/9*b^2*(b*x+a)^(3/2)*(d*x+c)^(3/4)/d^3-224/15*b^2*(-a*d+b*c)*(d*x+c)^(3 /4)*(b*x+a)^(1/2)/d^4+448/15*b^(5/4)*(-a*d+b*c)^(11/4)*EllipticE(b^(1/4)*( d*x+c)^(1/4)/(-a*d+b*c)^(1/4),I)*(-d*(b*x+a)/(-a*d+b*c))^(1/2)/d^5/(b*x+a) ^(1/2)-448/15*b^(5/4)*(-a*d+b*c)^(11/4)*EllipticF(b^(1/4)*(d*x+c)^(1/4)/(- a*d+b*c)^(1/4),I)*(-d*(b*x+a)/(-a*d+b*c))^(1/2)/d^5/(b*x+a)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.06 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.26 \[ \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx=\frac {2 (a+b x)^{9/2} \left (\frac {b (c+d x)}{b c-a d}\right )^{9/4} \operatorname {Hypergeometric2F1}\left (\frac {9}{4},\frac {9}{2},\frac {11}{2},\frac {d (a+b x)}{-b c+a d}\right )}{9 b (c+d x)^{9/4}} \]
(2*(a + b*x)^(9/2)*((b*(c + d*x))/(b*c - a*d))^(9/4)*Hypergeometric2F1[9/4 , 9/2, 11/2, (d*(a + b*x))/(-(b*c) + a*d)])/(9*b*(c + d*x)^(9/4))
Time = 0.49 (sec) , antiderivative size = 338, normalized size of antiderivative = 1.18, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.579, Rules used = {57, 57, 60, 60, 73, 836, 765, 762, 1390, 1388, 327}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx\) |
\(\Big \downarrow \) 57 |
\(\displaystyle \frac {14 b \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/4}}dx}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 57 |
\(\displaystyle \frac {14 b \left (\frac {10 b \int \frac {(a+b x)^{3/2}}{\sqrt [4]{c+d x}}dx}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}}dx}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {2 (b c-a d) \int \frac {1}{\sqrt {a+b x} \sqrt [4]{c+d x}}dx}{5 d}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \int \frac {\sqrt {c+d x}}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{5 d^2}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 836 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {\sqrt {b c-a d} \int \frac {1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}\right )}{5 d^2}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 765 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {1}{\sqrt {1-\frac {b (c+d x)}{b c-a d}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 762 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}d\sqrt [4]{c+d x}}{\sqrt {b}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 1390 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}{\sqrt {1-\frac {b (c+d x)}{b c-a d}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 1388 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {\sqrt {b c-a d} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \int \frac {\sqrt {\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}+1}}{\sqrt {1-\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}}}d\sqrt [4]{c+d x}}{\sqrt {b} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
\(\Big \downarrow \) 327 |
\(\displaystyle \frac {14 b \left (\frac {10 b \left (\frac {4 (a+b x)^{3/2} (c+d x)^{3/4}}{9 d}-\frac {2 (b c-a d) \left (\frac {4 \sqrt {a+b x} (c+d x)^{3/4}}{5 d}-\frac {8 (b c-a d) \left (\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} E\left (\left .\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}-\frac {(b c-a d)^{3/4} \sqrt {1-\frac {b (c+d x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{b^{3/4} \sqrt {a+\frac {b (c+d x)}{d}-\frac {b c}{d}}}\right )}{5 d^2}\right )}{3 d}\right )}{d}-\frac {4 (a+b x)^{5/2}}{d \sqrt [4]{c+d x}}\right )}{5 d}-\frac {4 (a+b x)^{7/2}}{5 d (c+d x)^{5/4}}\) |
(-4*(a + b*x)^(7/2))/(5*d*(c + d*x)^(5/4)) + (14*b*((-4*(a + b*x)^(5/2))/( d*(c + d*x)^(1/4)) + (10*b*((4*(a + b*x)^(3/2)*(c + d*x)^(3/4))/(9*d) - (2 *(b*c - a*d)*((4*Sqrt[a + b*x]*(c + d*x)^(3/4))/(5*d) - (8*(b*c - a*d)*((( b*c - a*d)^(3/4)*Sqrt[1 - (b*(c + d*x))/(b*c - a*d)]*EllipticE[ArcSin[(b^( 1/4)*(c + d*x)^(1/4))/(b*c - a*d)^(1/4)], -1])/(b^(3/4)*Sqrt[a - (b*c)/d + (b*(c + d*x))/d]) - ((b*c - a*d)^(3/4)*Sqrt[1 - (b*(c + d*x))/(b*c - a*d) ]*EllipticF[ArcSin[(b^(1/4)*(c + d*x)^(1/4))/(b*c - a*d)^(1/4)], -1])/(b^( 3/4)*Sqrt[a - (b*c)/d + (b*(c + d*x))/d])))/(5*d^2)))/(3*d)))/d))/(5*d)
3.17.71.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & & GtQ[n, 0] && LtQ[m, -1] && !(IntegerQ[n] && !IntegerQ[m]) && !(ILeQ[m + n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c , d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[ (Sqrt[a]/(Sqrt[c]*Rt[-d/c, 2]))*EllipticE[ArcSin[Rt[-d/c, 2]*x], b*(c/(a*d) )], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[a, 0]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[(1/(Sqrt[a]*Rt[-b/a, 4]) )*EllipticF[ArcSin[Rt[-b/a, 4]*x], -1], x] /; FreeQ[{a, b}, x] && NegQ[b/a] && GtQ[a, 0]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[Sqrt[1 + b*(x^4/a)]/Sqrt [a + b*x^4] Int[1/Sqrt[1 + b*(x^4/a)], x], x] /; FreeQ[{a, b}, x] && NegQ [b/a] && !GtQ[a, 0]
Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[-b/a, 2]}, Simp[-q^(-1) Int[1/Sqrt[a + b*x^4], x], x] + Simp[1/q Int[(1 + q*x^2)/S qrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && NegQ[b/a]
Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.))^(p_.)*((d_) + (e_.)*(x_)^(n_))^(q_.), x_Symbol] :> Int[u*(d + e*x^n)^(p + q)*(a/d + (c/e)*x^n)^p, x] /; FreeQ[{a, c, d, e, n, p, q}, x] && EqQ[n2, 2*n] && EqQ[c*d^2 + a*e^2, 0] && (Integer Q[p] || (GtQ[a, 0] && GtQ[d, 0]))
Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> Simp[Sqrt [1 + c*(x^4/a)]/Sqrt[a + c*x^4] Int[(d + e*x^2)/Sqrt[1 + c*(x^4/a)], x], x] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 + a*e^2, 0] && NegQ[c/a] && !GtQ [a, 0] && !(LtQ[a, 0] && GtQ[c, 0])
\[\int \frac {\left (b x +a \right )^{\frac {7}{2}}}{\left (d x +c \right )^{\frac {9}{4}}}d x\]
\[ \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {7}{2}}}{{\left (d x + c\right )}^{\frac {9}{4}}} \,d x } \]
integral((b^3*x^3 + 3*a*b^2*x^2 + 3*a^2*b*x + a^3)*sqrt(b*x + a)*(d*x + c) ^(3/4)/(d^3*x^3 + 3*c*d^2*x^2 + 3*c^2*d*x + c^3), x)
\[ \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx=\int \frac {\left (a + b x\right )^{\frac {7}{2}}}{\left (c + d x\right )^{\frac {9}{4}}}\, dx \]
\[ \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {7}{2}}}{{\left (d x + c\right )}^{\frac {9}{4}}} \,d x } \]
\[ \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {7}{2}}}{{\left (d x + c\right )}^{\frac {9}{4}}} \,d x } \]
Timed out. \[ \int \frac {(a+b x)^{7/2}}{(c+d x)^{9/4}} \, dx=\int \frac {{\left (a+b\,x\right )}^{7/2}}{{\left (c+d\,x\right )}^{9/4}} \,d x \]